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Status Functionality already exists
Created by Guest
Created on Feb 3, 2021

Include multiplier operator on filter

The multiplier operator only works on the query paramter. -https://cloud.ibm.com/docs/discovery?topic=discovery-query-operators#multiplier


It would be useful if it could be used on the filter paramter or at least specify in the documentation that its a query exclusive operator.

  • Guest
    Feb 5, 2021

    I made the incorrect assumption that natural language query (returning passages) gives the same results as a structure query using the ’:’ operator. Please refer to the following post: https://www.ibm.com/mysupport/s/forumsquestion?id=0D53p00008SBMe6CAH

    In this case a multiplier operator on the filter parameter is a possible solution.

  • Guest
    Feb 3, 2021

    Given documents with fields product and text.


    Currently, I use a natural language query and filter by specific products as follows:

    Query:text:Where is this?

    Filter:product::product1|product:product2


    I want to filter by the product field whilst weighting specific product fields with the multiplier operator. In the above example, I use the multiplier on product2 to improve its score. I would expect the following...

    Query:text:Where is this?

    Filter:product::product1|product::product2^2


    At this point, I cannot use the multiplier on the filter; therefore, I would use my filter query on the query parameter instead of the filter parameter. To achieve the results, I'm looking for I have to do the following query...

    Query:text:Where is this?,(product::product1|product::product2^2)


    I understand the query is used to impact score; however, in my use case filter becomes redundant as I'm forced to filter using the query parameter. I think it would be useful to specify this in the documentation to be clear.

  • Guest
    Feb 3, 2021

    Hi Philip - what are you trying to do with the operator in filter exactly? I believe in query it's used to impact score however filter is not scored, thus nothing that affects score would be applicable