Include multiplier operator on filter

I made the incorrect assumption that natural language query (returning passages) gives the same results as a structure query using the ’:’ operator. Please refer to the following post: https://www.ibm.com/mysupport/s/forumsquestion?id=0D53p00008SBMe6CAH

In this case a multiplier operator on the filter parameter is a possible solution.

Given documents with fields product and text.

Currently, I use a natural language query and filter by specific products as follows:

Query:text:Where is this?

Filter:product::product1|product:product2

I want to filter by the product field whilst weighting specific product fields with the multiplier operator. In the above example, I use the multiplier on product2 to improve its score. I would expect the following...

Query:text:Where is this?

Filter:product::product1|product::product2^2

At this point, I cannot use the multiplier on the filter; therefore, I would use my filter query on the query parameter instead of the filter parameter. To achieve the results, I'm looking for I have to do the following query...

Query:text:Where is this?,(product::product1|product::product2^2)

I understand the query is used to impact score; however, in my use case filter becomes redundant as I'm forced to filter using the query parameter. I think it would be useful to specify this in the documentation to be clear.

Hi Philip - what are you trying to do with the operator in filter exactly? I believe in query it's used to impact score however filter is not scored, thus nothing that affects score would be applicable